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14x^2+-110x+84=0
We add all the numbers together, and all the variables
14x^2-110x=0
a = 14; b = -110; c = 0;
Δ = b2-4ac
Δ = -1102-4·14·0
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-110}{2*14}=\frac{0}{28} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+110}{2*14}=\frac{220}{28} =7+6/7 $
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